6x^2+25x=129

Solution for 6x^2+25x=129 equation:

6x^2+25x=129

We move all terms to the left:

6x^2+25x-(129)=0

a = 6; b = 25; c = -129;
Δ = b2-4ac
Δ = 252-4·6·(-129)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-61}{2*6}=\frac{-86}{12}
=-7+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+61}{2*6}=\frac{36}{12}
=3
$